GetWordPosition should ignore special characters now
chinese sentence doesnt have space as word separator nor a word separator at all, same goes for thai,etc. iirc :)
This commit is contained in:
xsftk 2017-11-11 15:04:58 +07:00
parent 91008be48d
commit 4f3e2565a4

View File

@ -133,15 +133,15 @@ namespace NadekoBot.Modules.CustomReactions.Extensions
if (indexOfWord == 0) // on start
{
if (word.Length < str.Length &&str.isInvalidWordChar(word.Length)) // filter char after word index
if (word.Length < str.Length && str.isInvalidWordChar(word.Length)) // filter char after word index
return WordPosition.Start;
}
else if ((indexOfWord + word.Length) == str.Length) // on end
{
if (str.isInvalidWordChar(indexOfWord-1)) // filter char before word index
if (str.isInvalidWordChar(indexOfWord - 1)) // filter char before word index
return WordPosition.End;
}
else if (str.isInvalidWordChar(indexOfWord-1) && str.isInvalidWordChar(indexOfWord + word.Length)) // on middle
else if (str.isInvalidWordChar(indexOfWord - 1) && str.isInvalidWordChar(indexOfWord + word.Length)) // on middle
return WordPosition.Middle;
return WordPosition.None;
@ -149,10 +149,10 @@ namespace NadekoBot.Modules.CustomReactions.Extensions
private static bool isInvalidWordChar(this string str, int index)
{
var ch = str[index];
if ((byte)ch > 64 && (byte)ch <= 90) // must be A-Z
var ch = (ushort)str[index];
if (ch > 64 && ch <= 90) // must be A-Z
return false;
if ((byte)ch > 97 && (byte)ch <= 122) // a-z
if (ch > 97 && ch <= 122) // a-z
return false;
return true;